document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341238>Question 341238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are complementary. the measure of one angle is 21 more than twice the measure of the other angle.find the measure of the angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244319 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If two angles are complementary, they add to 90.\r<BR>\n" );
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document.write( "Thus the angles are x and 90-x (that's tricky, reason it out why it is so)...<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "(90-x) = 21 + 2x<BR>\n" );
document.write( "90 - x = 21 + 2x<BR>\n" );
document.write( "Now subtract 21 and add x to both sides in two steps...<BR>\n" );
document.write( "69 = 3x<BR>\n" );
document.write( "x = 23<BR>\n" );
document.write( "90-x = 67 </SPAN>\n" );
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