document.write( "Question 341148: What are the different combinations of nickels, dimes, and/or quarters that equal exactly 45 cents? \n" ); document.write( "
Algebra.Com's Answer #244310 by Edwin McCravy(20060)\"\" \"About 
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document.write( "The equation is:\r\n" );
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document.write( "5n + 10d + 25q = 45\r\n" );
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document.write( "It can be divided through by 5\r\n" );
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document.write( "n + 2d + 5q = 9\r\n" );
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document.write( "We will consider two cases\r\n" );
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document.write( "Case 1.  Using no quarters, i.e., q=0, then\r\n" );
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document.write( "n + 2d + 5(0) = 9\r\n" );
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document.write( "n + 2d = 9\r\n" );
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document.write( "d = \"%289-n%29%2F2\"\r\n" );
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document.write( "n must be an odd number to make the numerator even so it\r\n" );
document.write( "can be divided evenly by the denominator 2.\r\n" );
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document.write( "1.  n=1 nickel, \"%289-1%29%2F2=8%2F2=%22%22\"4 dimes\r\n" );
document.write( "2.  n=3 nickels, \"%289-3%29%2F2=6%2F2=%22%22\"3 dimes.\r\n" );
document.write( "3.  n=5 nickels, \"%289-5%29%2F2=4%2F2=%22%22\"2 dimes.\r\n" );
document.write( "4.  n=7 nickels, \"%289-7%29%2F2=2%2F2=%22%22\"1 dime.\r\n" );
document.write( "5.  n=9 nickels, \"%289-9%29%2F2=0%2F2=%22%22\"0 dimes.\r\n" );
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document.write( "Case 2. q=1\r\n" );
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document.write( "n + 2d + 5(1) = 9\r\n" );
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document.write( "n + 2d + 5 = 9\r\n" );
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document.write( "n + 2d = 4\r\n" );
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document.write( "d = \"%284-n%29%2F2\"\r\n" );
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document.write( "n must be an even number to make the numerator even so it\r\n" );
document.write( "can be divided evenly by the denominator 2.  (Don't forget\r\n" );
document.write( "that 0 is an even number!)\r\n" );
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document.write( "6.  n=0 nickels, \"%284-0%29%2F2=4%2F2=%22%22\"2 dimes\r\n" );
document.write( "7.  n=2 nickels, \"%284-2%29%2F2=2%2F2=%22%22\"1 dime.\r\n" );
document.write( "8.  n=4 nickels, \"%284-4%29%2F2=0%2F2=%22%22\"0 dimes.\r\n" );
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document.write( "So there are 8 ways to make 45 cents using nickels and/or dimes and/or \r\n" );
document.write( "quarters. \r\n" );
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document.write( "Edwin
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