document.write( "Question 340942: Here we go again, with story problems. I just cant seem to get them right so will you please help me.\r
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document.write( "Jodie bicycles 6 km/h faster than Robert. In the same time it takes Robert to bicycle 48 km Jodie can bicycle 66km. how fast does each bicyclist travel?\r
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document.write( "Robert travels ___________ km/h
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document.write( "Jodie travels ____________ km/h\r
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document.write( "Thanks :o) \n" );
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Algebra.Com's Answer #244277 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jodie bicycles 6 km/h faster than Robert. \n" ); document.write( " In the same time it takes Robert to bicycle 48 km Jodie can bicycle 66km. \n" ); document.write( " how fast does each bicyclist travel? \n" ); document.write( ": \n" ); document.write( "Let s = R's speed \n" ); document.write( "then \n" ); document.write( "(s+6) = J's speed \n" ); document.write( ": \n" ); document.write( "Write a time equation; Time = dist/speed \n" ); document.write( ": \n" ); document.write( "J's time = R's time \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross mulltiply \n" ); document.write( "66s = 48(s+6) \n" ); document.write( "66s = 48s + 288 \n" ); document.write( "66s - 48s = 288 \n" ); document.write( "18s = 288 \n" ); document.write( "s = \n" ); document.write( "s = 16 km/ hr is R's speed \n" ); document.write( "then \n" ); document.write( "16 + 2 = 22 km/hr is J's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check these solutions, find the times of each (they should be equal) \n" ); document.write( "66/22 = 3 hrs \n" ); document.write( "48/16 = 3 hrs \n" ); document.write( ": \n" ); document.write( "That wasn't that hard, now was it. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |