document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=341194>Question 341194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244272 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y + z = 180<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "z = 3y-12<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Substitute and solve for \"y\";<BR>\n" );
document.write( "2y + y + 3y-12 = 180<BR>\n" );
document.write( "6y = 192<BR>\n" );
document.write( "y = 32 degrees<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 2y = 64 degrees<BR>\n" );
document.write( "z = 3y-12 = 96-12 = 84 degrees<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );