document.write( "Question 341163: How do you solve for:\r
\n" ); document.write( "\n" ); document.write( "x+12y=6
\n" ); document.write( "x-1/3y=4
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Algebra.Com's Answer #244258 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve for:
\n" ); document.write( "x+12y=6
\n" ); document.write( "x-1/3y=4
\n" ); document.write( "---------------
\n" ); document.write( "Subtract the 2nd from the 1st equation to get:
\n" ); document.write( "12 1/3 y = 2
\n" ); document.write( "---
\n" ); document.write( "(37/3)y = 2
\n" ); document.write( "y = 2(3/37)
\n" ); document.write( "y = 6/37
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\n" ); document.write( "Substitue for y in (x +12y = 6) and solve for \"x\":
\n" ); document.write( "x + 12(6/37) = 6
\n" ); document.write( "---
\n" ); document.write( "x + 72/37 = 6
\n" ); document.write( "x = 150/37
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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