document.write( "Question 341163: How do you solve for:\r
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document.write( "x+12y=6
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document.write( "x-1/3y=4 \n" );
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Algebra.Com's Answer #244258 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! solve for: \n" ); document.write( "x+12y=6 \n" ); document.write( "x-1/3y=4 \n" ); document.write( "--------------- \n" ); document.write( "Subtract the 2nd from the 1st equation to get: \n" ); document.write( "12 1/3 y = 2 \n" ); document.write( "--- \n" ); document.write( "(37/3)y = 2 \n" ); document.write( "y = 2(3/37) \n" ); document.write( "y = 6/37 \n" ); document.write( "============= \n" ); document.write( "Substitue for y in (x +12y = 6) and solve for \"x\": \n" ); document.write( "x + 12(6/37) = 6 \n" ); document.write( "--- \n" ); document.write( "x + 72/37 = 6 \n" ); document.write( "x = 150/37 \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |