document.write( "Question 341023: I need help solving this problem. I keep getting the wrong answer. 5=.0002x^2-.316x+127.9. If you could help I would greatly appriciate it. \n" ); document.write( "
Algebra.Com's Answer #244217 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
5=.0002x^2-.316x+127.9
\n" ); document.write( "\"0.0002x%5E2+-+0.316x+%2B+112.9+=+0\"
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"0.0002x%5E2%2B-0.316x%2B112.9+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-0.316%29%5E2-4%2A0.0002%2A112.9=0.00953599999999999\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=0.00953599999999999 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--0.316%2B-sqrt%28+0.00953599999999999+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"0.0002x%5E2%2B-0.316x%2B112.9\" can be factored:
\n" ); document.write( " \"0.0002x%5E2%2B-0.316x%2B112.9+=+%28x-1034.13111231467%29%2A%28x-545.868887685326%29\"
\n" ); document.write( " Again, the answer is: 1034.13111231467, 545.868887685326.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+0.0002%2Ax%5E2%2B-0.316%2Ax%2B112.9+%29\"

\n" ); document.write( "\n" ); document.write( "----------------
\n" ); document.write( "Ignore the part about factoring it.
\n" ); document.write( "
\n" ); document.write( "
\n" );