document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=340964>Question 340964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact value of cot(-315deg)<BR>\n" );
document.write( "a. 1<BR>\n" );
document.write( "b. sqrt 2<BR>\n" );
document.write( "c. sqrt/2<BR>\n" );
document.write( "d. 2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244210 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you go -315 degrees, you basically go clockwise and end up in quadrant I at 45 degrees, here <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"x=sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"y=sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "--<BR>\n" );
document.write( "Cot(theta) = x/y<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cot%28-315%29=cot%2845%29=%28sqrt%282%29%2F2%29%2F%28sqrt%282%29%2F2%29=1 ALIGN=MIDDLE  ALT=\"cot%28-315%29=cot%2845%29=%28sqrt%282%29%2F2%29%2F%28sqrt%282%29%2F2%29=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );