document.write( "Question 340988: When Frank drives to work his trip takes 40 mintues, but when he takes the train it takes 30 mintues. Find the distance Frank travels to work if the train travels an average of 15 miles per hour faster then his driving. \n" ); document.write( "
Algebra.Com's Answer #244205 by stanbon(75887)\"\" \"About 
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When Frank drives to work his trip takes 40 mintues, but when he takes the train it takes 30 mintues. Find the distance Frank travels to work if the train travels an average of 15 miles per hour faster then his driving.
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\n" ); document.write( "Car DATA:
\n" ); document.write( "time = 2/3 hr ; distance = x miles: rate = x/(2/3) mph = (3/2)x mph
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\n" ); document.write( "Train DATA:
\n" ); document.write( "time = 1/2 hr ; distance = x miles; rate = x/(1/2) mph = 2x mph
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\n" ); document.write( "Equation:
\n" ); document.write( "tain rate - car rate = 15
\n" ); document.write( "2x - (3/2)x = 15 mph
\n" ); document.write( "(1/2)x = 15 mph
\n" ); document.write( "x = 30 miles (distance Frank travels to work)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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