document.write( "Question 340963: Your word problem on the first page was changed from \"A freight train leaves the station traveling (50) miles an hour and a passenger train leaves the station 30 minutes later traveling (70) miles per hour. How long will it take for the passenger train to catch up with the freight train?\" to a totally different word problem no matter what tab I clicked. This was not helpful to me. Please show me how to set up a formula to solve this problem. \n" ); document.write( "
Algebra.Com's Answer #244202 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A freight train leaves the station traveling (50) miles an hour and a passenger train leaves the station 30 minutes later traveling (70) miles per hour. How long will it take for the passenger train to catch up with the freight train? \n" ); document.write( ". \n" ); document.write( "Apply the distance formula of: \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance (miles) \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time (hours) \n" ); document.write( ". \n" ); document.write( "Realize that 30 minutes = .5 hours \n" ); document.write( ". \n" ); document.write( "Let x = hours traveled by the freight train \n" ); document.write( "then \n" ); document.write( "x - .5 = hours traveled by the passenger train \n" ); document.write( ". \n" ); document.write( "\"distance traveled by freight train\" = \"distance traveled by passenger train\" \n" ); document.write( "50x = 70(x-.5) \n" ); document.write( "50x = 70x-35 \n" ); document.write( "-20x = -35 \n" ); document.write( "x = 1.75 hours \n" ); document.write( "or \n" ); document.write( "x = 1 hour and 45 minutes\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |