document.write( "Question 340924: f(x)=sqrt(x+1/x-5) the domain is (-infinity,-1)u(5,infinity) does the inequality sign on the top of the fraction point the opposit way. When solving I started out with x+1>or equal to 0 and x-5>or equal to 0 so my answer was
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document.write( "(-1,5)u(5,infinity) where did I go wrong? Are all functions able to be solved to discover their domain or is it a guessing game? \n" );
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Algebra.Com's Answer #244189 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You have a function that involves both a radical with an even index (square root in this case) and a rational function (one expression divided by another). You must restrict your domain such that the expression under the radical is greater than or equal to zero and you must also restrict it so that the denominator of the rational expression does not equal zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Restricting the denominator of the rational part of your function is simple in this case. You simply cannot let the value of your independent variable, ( \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Restricting the radicand to zero or positive is a bit more complex.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that if \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In summary, the domain is -1 or anything smaller and anything larger than 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, in interval notation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice the bracket vice parentheses on the -1 end of the first interval. That includes the -1 endpoint as opposed to use of the parentheses on the 5 end of the second interval where we want to exclude the endpoint 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |