document.write( "Question 340872: if (x+3)/2 is an integer, then x must be\r
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Algebra.Com's Answer #244162 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B3%29%2F2\" is an integer
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document.write( "First we look at the 2 denominator.  In order for \"%28x%2B3%29%2F2\"\r\n" );
document.write( "to end up being an integer the numerator \"x%2B3\" must\r\n" );
document.write( "be divisible by 2, which means that the whole numerator \"x%2B3\" \r\n" );
document.write( "must end up being an even integer.\r\n" );
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document.write( "Now we remember the rules for adding even and odd integers\r\n" );
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document.write( "1. even + even = even\r\n" );
document.write( "2. even + odd = odd\r\n" );
document.write( "3. odd + odd = even\r\n" );
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document.write( "We want \"x%2B3\" to end up an even integer.\r\n" );
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document.write( "Now since \"3\" is odd, in order for \"x%2B3\" to be an\r\n" );
document.write( "even integer we must have the 3rd case.  That is, the only way \r\n" );
document.write( "to get an even integer for \"x%2B3\" is to add an odd integer \r\n" );
document.write( "to the odd integer 3.\r\n" );
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document.write( "Therefore the correct answer is E.\r\n" );
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document.write( "Edwin
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