document.write( "Question 340835: the area of a triangle is 27 square feet. Its height is three time the length of its base. Find the height and base of the triangle\r
\n" ); document.write( "\n" ); document.write( "I tried 27=1/2b + 3b but couldn't get it to work out. Can you please explain.
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Algebra.Com's Answer #244147 by mananth(16949)\"\" \"About 
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let base be x
\n" ); document.write( "height = 3x
\n" ); document.write( "area = 1/2 * base* height
\n" ); document.write( "area = 1/2 * x*3x
\n" ); document.write( "Area = 3x^2/2= 27
\n" ); document.write( "3x^2= 54
\n" ); document.write( "x^2= 54/3
\n" ); document.write( "x^2= 18
\n" ); document.write( "x= sqrt 18
\n" ); document.write( "x= sqrt (3*3*2)
\n" ); document.write( "x= 3sqrt2 the base
\n" ); document.write( "height = 3 * 3sqrt2
\n" ); document.write( "height = 9 sqrt2
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