document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38962>Question 38962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a picture is 4 feet less than twice its width. To frame it, 76 feet of framing are needed. Find the dimensions of the picture.\r<BR>\n" );
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document.write( "(This is not from a textbook) Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24411 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width.<BR>\n" );
document.write( "The length is 2w - 4.<BR>\n" );
document.write( "The perimeter, 76, is 2L + 2w, so we have<BR>\n" );
document.write( "P = 2L + 2w<BR>\n" );
document.write( "76 = 2(2w - 4) + 2w<BR>\n" );
document.write( "76 = 4w - 8 + 2w<BR>\n" );
document.write( "76 = 6w - 8<BR>\n" );
document.write( "84 = 6w <BR>\n" );
document.write( "w = 14<BR>\n" );
document.write( "L = 2w - 4 = 20 </SPAN>\n" );
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