document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38961>Question 38961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! Can you help me with this problem?<BR>\n" );
document.write( "One number is 4 times another number. The larger number is also 87 more than the smaller number. Find the numbers.<BR>\n" );
document.write( "If you could help me it would be very much appreciated.<BR>\n" );
document.write( "Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24410 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the smaller and y be the larger.<BR>\n" );
document.write( "so we have<BR>\n" );
document.write( "y = 4x and<BR>\n" );
document.write( "y - x = 87<BR>\n" );
document.write( "Now substituting we have<BR>\n" );
document.write( "4x - x = 87<BR>\n" );
document.write( "3x  = 87<BR>\n" );
document.write( "x = 29<BR>\n" );
document.write( "y = 4x = 116 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );