document.write( "Question 340712: Find the zeros (or roots)\r
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Algebra.Com's Answer #244091 by Edwin McCravy(20055)\"\" \"About 
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Find the zeros (or roots)\r
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document.write( "Factor the expression as the difference of cubes:\r\n" );
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document.write( "\"%28x-2%29%28x%5E2%2B2x%2B4%29=0\"\r\n" );
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document.write( "Set each factor = 0\r\n" );
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document.write( "Setting \"x-2=0\"\r\n" );
document.write( "Solution: \"x=2\"\r\n" );
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document.write( "Setting the second factor = 0:\r\n" );
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document.write( "\"x%5E2%2B2x%2B4=0\"\r\n" );
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r\n" );
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document.write( "\"x+=+%28-%282%29+%2B-+sqrt%28%282%29%5E2-4%2A%281%29%2A%284%29+%29%29%2F%282%2A%281%29%29+\" \r\n" );
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document.write( "\"x+=+%28-2+%2B-+sqrt%284-16%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-2+%2B-+sqrt%28-12%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-2+%2B-+i%2Asqrt%2812%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-2+%2B-+i%2Asqrt%284%2A3%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28-2+%2B-+2i%2Asqrt%283%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%282%28-1+%2B-+i%2Asqrt%283%29%29%29%2F2+\"\r\n" );
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document.write( "\"x+=+%28cross%282%29%28-1+%2B-+i%2Asqrt%283%29%29%29%2Fcross%282%29+\"\r\n" );
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document.write( "\"x+=+-1+%2B-+i%2Asqrt%283%29+\"\r\n" );
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document.write( "The three solutions are\r\n" );
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document.write( "\"x=2\", \"x+=+-1+%2B+i%2Asqrt%283%29+\", \"x+=+-1+-+i%2Asqrt%283%29+\"\r\n" );
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document.write( "Edwin
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