document.write( "Question 340529: allen111@purdue.edu\r
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Algebra.Com's Answer #244083 by Edwin McCravy(20081)\"\" \"About 
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\"Sec%28theta%29=-1.5\" \"pi%2F2%3Ctheta%3Cpi\"\r
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document.write( "We change \"-1.5\" to the fraction \"-3%2F2\"\r\n" );
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document.write( "Since \"Sec%28theta%29=-3%2F2\" we draw q in Quadrant II\r\n" );
document.write( "and since \"Sec%28theta%29=r%2Fx\" we label the value of r as 3,\r\n" );
document.write( "the numerator of \"-3%2F2\", considering it as \"3%2F%28-2%29\",\r\n" );
document.write( "and we label the value of x as the denominator -2.\r\n" );
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document.write( "Then we calculate the value of y by the Pythagorean relation:\r\n" );
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document.write( "\"x%5E2%2By%5E2=r%5E2\"\r\n" );
document.write( "\"%28-2%29%5E2%2By%5E2=3%5E2\"\r\n" );
document.write( "\"4%2By%5E2=9\"\r\n" );
document.write( "\"y%5E2=5\"\r\n" );
document.write( "\"y=sqrt%285%29\"\r\n" );
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document.write( "So we now label y as \"sqrt%285%29\"\r\n" );
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document.write( "Now the trig functions for q are:\r\n" );
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document.write( "\"sin%28theta%29=y%2Fr=sqrt%285%29%2F3\"\r\n" );
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document.write( "\"cos%28theta%29=x%2Fr=%28-2%29%2F3=-2%2F3\"\r\n" );
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document.write( "\"tan%28theta%29=y%2Fx=sqrt%285%29%2F-2=-sqrt%285%29%2F2\"\r\n" );
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document.write( "\"sec%28theta%29=r%2Fx=3%2F%28-2%29=-3%2F2\"\"%28given%29\"\r\n" );
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document.write( "Edwin
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