document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=340519>Question 340519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If an object is thrown upward with an initial velocity of 96ft. per second, its height after 1 sec. is given by h=96t + 16t^2. Find the number of seconds before the object hits the ground. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #244006 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=244006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If an object is thrown upward with an initial velocity of 96ft. per second, its height after 1 sec. is given by h=96t + 16t^2. Find the number of seconds before the object hits the ground.<BR>\n" );
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document.write( "Your equation is not right, it's h(t) = 96t - 16t^2.  If it's +16t^2, it would never stop going up.<BR>\n" );
document.write( "h(t) = -16t^2 + 96t<BR>\n" );
document.write( "It's a ground level when h(t) = 0<BR>\n" );
document.write( "h(t) = -16t^2 + 96t = 0<BR>\n" );
document.write( "16t^2 = 96t<BR>\n" );
document.write( "t = 0 (at the start)<BR>\n" );
document.write( "t = 6 seconds (at impact)<BR>\n" );
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