document.write( "Question 4939: determine f-1 for f(x) = cubed root of(x+5) \r
\n" ); document.write( "\n" ); document.write( "(in f -1) is not f minus 1 or the negative 1 power of f)
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Algebra.Com's Answer #2440 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
By \"f%5E%28-1%29%28x%29+=+cuberoot+%28x%2B5%29+\" you refer to the inverse of the function f(x). Am I right?\r
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\n" ); document.write( "\n" ); document.write( "Given y = cuberoot (x+5)
\n" ); document.write( "My approach to finding an inverse of f(x) is two steps.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Interchange the x and y.
\n" ); document.write( "x= cuberoot (y+5)\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Solve for y.
\n" ); document.write( "To undo the cuberoot, you must cube both sides:
\n" ); document.write( "\"x%5E3+=+y%2B5+\"\r
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\n" ); document.write( "\n" ); document.write( "Next, undo the +5 by subtracting 5 from each side:
\n" ); document.write( "\"x%5E3+-+5+=+y\"\r
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\n" ); document.write( "\n" ); document.write( "This new y that you just solved for the the inverse function for f(x)\r
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\n" ); document.write( "\n" ); document.write( "The inverse function for \"f%28X%29+=+cuberoot+of+%28x%2B5%29+\" is \"f%5E%28-1%29+%28x%29+=+x%5E3+-+5+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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