document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38952>Question 38952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! I have trouble with this word problem. Can you help me?<BR>\n" );
document.write( "A rectangle and square have the same width, but the rectangles length is 5m longer than the squares. Their area is 133m(squared). Find the dimensions.\r<BR>\n" );
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document.write( "I have tried <BR>\n" );
document.write( "rectange=l+5  <BR>\n" );
document.write( "square= l   \r<BR>\n" );
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document.write( "          then I did l+l+5=133<BR>\n" );
document.write( "                        -5=-5<BR>\n" );
document.write( "                        2l=128<BR>\n" );
document.write( "                    i divided by 2 and got<BR>\n" );
document.write( "                          l=64m<BR>\n" );
document.write( "I dont think that is right. Can you help me?\r<BR>\n" );
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document.write( "If you could help me that would be great, but if not I'll try to work it out differently.<BR>\n" );
document.write( "Thanks,<BR>\n" );
document.write( "        Melissa </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24398 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's how you do it.<BR>\n" );
document.write( "Let w be the width of both.<BR>\n" );
document.write( "The square, then, has a length of w also.<BR>\n" );
document.write( "The rectangle has a length of w + 5.<BR>\n" );
document.write( "Now if we add the areas, we get a total of 133, so here goes...<BR>\n" );
document.write( "w^2 + w(w + 5) = 133<BR>\n" );
document.write( "2w^2 + 5w - 133 = 0<BR>\n" );
document.write( "(2w + 19)(w - 7) = 0<BR>\n" );
document.write( "w = -19/2 or w = 7<BR>\n" );
document.write( "but distance must be positive so w = 7.<BR>\n" );
document.write( "The length of the rectangle is 12. </SPAN>\n" );
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