document.write( "Question 340424: The average of the salaries of Kelly, Renee and Nina is 20,000 a year. If Kelly earns 4000 less than Renee and Nina's salary is two-thirds of Renee's salary, find the salary of each person.\r
\n" ); document.write( "\n" ); document.write( "I've tried setting up as follows;\r
\n" ); document.write( "\n" ); document.write( "Let R = Renee\r
\n" ); document.write( "\n" ); document.write( "Let R - 4000 = Kelly\r
\n" ); document.write( "\n" ); document.write( "Let 2/3 * R = Nina\r
\n" ); document.write( "\n" ); document.write( "R + ( R - 4000 ) + 2/3 * R = 20,000 \r
\n" ); document.write( "\n" ); document.write( "It's not working out for me though. Anyone have any thoughts? \n" ); document.write( "
Algebra.Com's Answer #243949 by alanc(27)\"\" \"About 
You can put this solution on YOUR website!
Your last equation is wrong. you don't sum the salaries to get the average. it should be divided by 3.\r
\n" ); document.write( "\n" ); document.write( "so
\n" ); document.write( "[R + ( R - 4000 ) + 2/3 * R ]/3 = 20,000 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "[R + R + 2/3 * R - 4000]/3 = [8R/3 - 4000]/3 = [8R/3 - 4000]/3 = 20000\r
\n" ); document.write( "\n" ); document.write( "[8R/3 - 4000] = 60000\r
\n" ); document.write( "\n" ); document.write( "64000 = 8R/3\r
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\n" ); document.write( "\n" ); document.write( "R = 64000* 3 /8 = 8000* 3 = 24000\r
\n" ); document.write( "\n" ); document.write( "Rene makes 24,000\r
\n" ); document.write( "\n" ); document.write( "Kelly makes 20,000\r
\n" ); document.write( "\n" ); document.write( "Nina makes 16,000\r
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