document.write( "Question 340391: Interest compounded continuously. Suppose that P 0 is invested in a savings account where interest is compounded continuously at 3.1% per year. * a) Express P(t) in terms of P0 and 0.031. * b) Suppose that $1000 is invested. What is the balance after 1 yr? after 2 y... \n" ); document.write( "
Algebra.Com's Answer #243942 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In general:\r
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\n" ); document.write( "\n" ); document.write( "So for 3.1% per year:\r
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\n" ); document.write( "\n" ); document.write( "For 1000 for 1 year:\r
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\n" ); document.write( "\n" ); document.write( "For 1000 for 2 years:\r
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\n" ); document.write( "\n" ); document.write( "I'll leave you alone to spend some quality time with your calculator.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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