document.write( "Question 340234: How many gallons of 80% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture that is 70% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #243934 by Fombitz(32388) $\"\"$ $\"About$

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Let $\"A\"$ be the amount of 80% solution.
\n" ); document.write( " $\"80A%2B25%2890%29=70%28A%2B90%29\"$
\n" ); document.write( " $\"80A%2B2250=70A%2B6300\"$
\n" ); document.write( " $\"10A=4050\"$
\n" ); document.write( " $\"A=405\"$ gallons \n" ); document.write( "

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