document.write( "Question 338228: 1. if it takes john 900 seconds to run 1 mile then he is running at a rate of 4 mph.
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Algebra.Com's Answer #243920 by Edwin McCravy(20062) $\"\"$ $\"About$

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1. if it takes john 900 seconds to run 1 mile then he is running at a rate of 4 mph.
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document.write( "Cancel the seconds:\r\n" );
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document.write( "All that's left is\r\n" );
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\n" ); document.write( "2. Three consecutive odd counting numbers have the property that the sum of the largest and twice the smallest is 64. what is the middle number.
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document.write( "Smallest of the three consecutive odd integers = n\r\n" );
document.write( "Middle of the three consecutive odd integers = (n+2)\r\n" );
document.write( "Largest of the three consecutive odd integers = (n+4)\r\n" );
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document.write( "largest + 2*smallest = 64\r\n" );
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document.write( "         (n+4) + 2*n = 64\r\n" );
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document.write( "         n + 4 + 2n  = 64\r\n" );
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document.write( "              3n + 4 = 64\r\n" );
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document.write( "                  3n = 60\r\n" );
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document.write( "                   n = 20\r\n" );
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document.write( "But 20 is even, not odd.  If the problem had asked for three consecutive\r\n" );
document.write( "even counting numbers, they would be\r\n" );
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document.write( "Smallest = n = 20\r\n" );
document.write( "Middle = (n+2) = 20+2 = 22\r\n" );
document.write( "Largest = (n+4) = 20+4 = 24\r\n" );
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document.write( "The largest, 24 plus twice the smallest, 2*20 or 40, is 64, since 24+40 = 64.\r\n" );
document.write( "But they're even, not odd.\r\n" );
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document.write( "Thus, there is no solution, since they must be odd.  Only such even\r\n" );
document.write( "consecutive counting numbers exist, but no odd ones. \r\n" );
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document.write( "Edwin

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