document.write( "Question 340403: There are two glasses of equal size, A and B. Glass A is empty and Glass B contains some water. Half of the water in glass b is poured into glass a. this process is repeated two more times - each time half of what is left in glass b is poured into glass a. at the end of these three pourings, glass a is half full. How much water is now left in glass b? \n" ); document.write( "
Algebra.Com's Answer #243916 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the amount of water in full glass units contained in glass B.\r
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\n" ); document.write( "\n" ); document.write( "After the first pouring,\r
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\n" ); document.write( "\n" ); document.write( "Glass A contains
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\n" ); document.write( "\n" ); document.write( "After the second pouring\r
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\n" ); document.write( "\n" ); document.write( "Glass A contains
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\n" ); document.write( "\n" ); document.write( "After the third pouring\r
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\n" ); document.write( "\n" ); document.write( "Glass A contains
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\n" ); document.write( "\n" ); document.write( "But since Glass A is now one-half full, we know that:\r
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\n" ); document.write( "\n" ); document.write( "of a glass full was the beginning amount in Glass B. Since Glass B now contains of the original amount, Glass B must now contain of a full glass.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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