document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38934>Question 38934</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sector of a circle has area 8.1pi cm squared and central angle 36 degrees. find its radius and arc length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24389 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well a sector of 36 degrees represents 1/10 of a circle...so the entire circle's area would be 81(pi)...setting that equal to the formula for area, we get<BR>\n" );
document.write( "81(pi) = (pi)r^2<BR>\n" );
document.write( "r^2 = 81<BR>\n" );
document.write( "r = 9<BR>\n" );
document.write( "Now the entire circumference is 2(pi)r = 18(pi), but we are talking about only 1/10 of a circle, thus the arc length is 1/10 of 18(pi), or 1.8(pi). </SPAN>\n" );
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