document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=340344>Question 340344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maria averaged 212 miles on the first day of her trip. She averaged only 104 miles on the last six days of her trip. What was the overall average number of miles driven per day?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243876 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the overall average is really a weighted average<BR>\n" );
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document.write( "weighted average = total miles driven/total days driven = (212+104)/7=45.14<BR>\n" );
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document.write( "alternatively, you could figure the miles each day and multiply by the proportion represented by each day.<BR>\n" );
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document.write( "for example, day 1 miles=212, day 2 miles =104/6=17.33, day 3 miles=17.33 etc<BR>\n" );
document.write( "each day represents 1/7 of the trip.<BR>\n" );
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document.write( "weighted average= 212*(1/7)+17.33*(1/7)+...17.33*(1/7)=212*(1/7)+17.33*(6/7)=45.14 </SPAN>\n" );
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