document.write( "Question 340370: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.
\n" ); document.write( "A rectangular platform is 11 feet longer than it is wide. If the area of the platform is 276 square feet, find the length and the width\r
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\n" ); document.write( "\n" ); document.write( "DOES ANYONE KNOW WHO TO SOLVE THIS PROBLEM? DO I MULITIPLY 275 X 11 TO GET THE LENGTH... PLEASE HELP!
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Algebra.Com's Answer #243871 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
let l=length
\n" ); document.write( "let w=width
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\n" ); document.write( "area of a rectangle =l*w
\n" ); document.write( "--
\n" ); document.write( "given
\n" ); document.write( "l=11+w
\n" ); document.write( "area=276
\n" ); document.write( "--
\n" ); document.write( "area=l*w
\n" ); document.write( "substitute l=11+w
\n" ); document.write( "\"276=%2811%2Bw%29%2Aw\"
\n" ); document.write( "\"276=11w%2Bw%5E2\"
\n" ); document.write( "\"0=w%5E2%2B11w-276\"
\n" ); document.write( "--
\n" ); document.write( "use quadratic equation to solve for w, using a=1,b=11,c=-276
\n" ); document.write( "\"w=%28-11-sqrt%2811%5E2-4%2A1%2A%28-276%29%29%29%2F%282%2A1%29=-23\" or \"w=%28-11%2Bsqrt%2811%5E2-4%2A1%2A%28-276%29%29%29%2F%282%2A1%29=12\"
\n" ); document.write( "since we are looking for a measurement, the negative result is ignored
\n" ); document.write( "\"highlight_red%28w=12%29\" and \"highlight_green%28l=11%2Bw=23%29\"
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