document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=340285>Question 340285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two planes which are 1860 miles apart travel toward each other. their speeds difer by 70mph. if they pass each other in 3 hours what are their speeds? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243809 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     two planes which are 1860 miles apart travel toward each other. their speeds difer by 70mph. if they pass each other in 3 hours what are their speeds?<BR>\n" );
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document.write( "Apply the distance forumla: d=rt<BR>\n" );
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document.write( "Let x = faster plane<BR>\n" );
document.write( "then<BR>\n" );
document.write( "x-70 = slower plane<BR>\n" );
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document.write( "3x + 3(x-70) = 1860<BR>\n" );
document.write( "Dividing both sides by 3:<BR>\n" );
document.write( "x + (x-70) = 620<BR>\n" );
document.write( "2x-70 = 620<BR>\n" );
document.write( "2x = 690<BR>\n" );
document.write( "x = 345 mph (faster plane)<BR>\n" );
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document.write( "Slower plane:<BR>\n" );
document.write( "x-70 = 345-70 = 275 mph<BR>\n" );
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