document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=340261>Question 340261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6(c-2)=7(c-6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243790 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From 6(c-2)=7(c-6),<BR>\n" );
document.write( "let's multiply out first, and get<BR>\n" );
document.write( "6c - 12 = 7c - 42<BR>\n" );
document.write( "now we want all the c's on one side and all the numbers on the other...<BR>\n" );
document.write( "so subtract 6c from both sides...<BR>\n" );
document.write( "-12 = c - 42<BR>\n" );
document.write( "now add 42 to both sides<BR>\n" );
document.write( "30 = c<BR>\n" );
document.write( "c = 30<BR>\n" );
document.write( "You can check the solution by plugging it back into the original equation... </SPAN>\n" );
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