document.write( "Question 38925: \r\n" );
document.write( "x³ + x - 2 = 0
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Algebra.Com's Answer #24377 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! We can see that x = 1 is a solution of \n" ); document.write( "x^3 + x - 2 = 0 \n" ); document.write( "but if we factor that expression by x - 1, we get \n" ); document.write( "(x - 1)(x^2 + x + 2) = 0 \n" ); document.write( "and the second polynomial is not factorable...you have to use the quadratic... \n" ); document.write( "so x = 1 and \n" ); document.write( "x = (-1 ± i*sqrt(7)) / 2 \n" ); document.write( " |