document.write( "Question 340067: sue drove at a rate of 45 mph from her home to her sister's house. she spent 1 1/2 hours having lunch with her sister. she then drove back home at a rate of 55 mph. the entire trip including lunch took 4 hours. how far does sue live from her sister? \n" ); document.write( "
Algebra.Com's Answer #243754 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! sue drove at a rate of 45 mph from her home to her sister's house. \n" ); document.write( " she spent 1 1/2 hours having lunch with her sister. \n" ); document.write( " she then drove back home at a rate of 55 mph. the entire trip including lunch took 4 hours. \n" ); document.write( " how far does sue live from her sister? \n" ); document.write( ": \n" ); document.write( "We are only interested in her travel time: 4 - 1.5 = 2.5 hrs \n" ); document.write( ": \n" ); document.write( "Let d = distance to sisters house (and back) \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply by 2475 (that's 45*55) to get rid of the denominators, results \n" ); document.write( "55d + 45d = 2475(2.5) \n" ); document.write( ": \n" ); document.write( "100d = 6187.5 \n" ); document.write( "d = \n" ); document.write( "d = 61.875 ~ 62 miles \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the time each way \n" ); document.write( "62/45 = 1.38 hrs \n" ); document.write( "62/55 = 1.13 hrs \n" ); document.write( "----------------- \n" ); document.write( "total: 2.51 hrs, close enough \n" ); document.write( " |