document.write( "Question 340067: sue drove at a rate of 45 mph from her home to her sister's house. she spent 1 1/2 hours having lunch with her sister. she then drove back home at a rate of 55 mph. the entire trip including lunch took 4 hours. how far does sue live from her sister? \n" ); document.write( "
Algebra.Com's Answer #243754 by ankor@dixie-net.com(22740)\"\" \"About 
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sue drove at a rate of 45 mph from her home to her sister's house.
\n" ); document.write( " she spent 1 1/2 hours having lunch with her sister.
\n" ); document.write( " she then drove back home at a rate of 55 mph. the entire trip including lunch took 4 hours.
\n" ); document.write( " how far does sue live from her sister?
\n" ); document.write( ":
\n" ); document.write( "We are only interested in her travel time: 4 - 1.5 = 2.5 hrs
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\n" ); document.write( "Let d = distance to sisters house (and back)
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\n" ); document.write( "Write a time equation: time = dist/speed
\n" ); document.write( "\"d%2F45\" + \"d%2F55\" = 2.5
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\n" ); document.write( "Multiply by 2475 (that's 45*55) to get rid of the denominators, results
\n" ); document.write( "55d + 45d = 2475(2.5)
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\n" ); document.write( "100d = 6187.5
\n" ); document.write( "d = \"6187.5%2F100\"
\n" ); document.write( "d = 61.875 ~ 62 miles
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\n" ); document.write( "Check solution by finding the time each way
\n" ); document.write( "62/45 = 1.38 hrs
\n" ); document.write( "62/55 = 1.13 hrs
\n" ); document.write( "-----------------
\n" ); document.write( "total: 2.51 hrs, close enough
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