document.write( "Question 339892: Solve \r
\n" ); document.write( "\n" ); document.write( "The square root of x+1, Under the square root of 3=the square root of 3x-5
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Algebra.Com's Answer #243683 by edjones(8007)\"\" \"About 
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sqrt(3)/sqrt(x+1)=sqrt(3x-5)
\n" ); document.write( "3/(x+1)=3x-5
\n" ); document.write( "3=3x^2-2x-5
\n" ); document.write( "3x^2-2x-8=0
\n" ); document.write( "3x^2-6x+4x-8=0
\n" ); document.write( "3x(x-2)+4(x-2)=0
\n" ); document.write( "3x+4=0, x-2=0
\n" ); document.write( "x=2
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\n" ); document.write( "Ed
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