document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339946>Question 339946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity x of a 80 % acid solution must be mixed with a 15 % solution to produce 600 mL of a 40 % solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243669 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .80X+.15(600-X)=.40*600<BR>\n" );
document.write( ".80X+90-.15X=240<BR>\n" );
document.write( ".65X=240-90<BR>\n" );
document.write( ".65X=150<BR>\n" );
document.write( "X=150/.65<BR>\n" );
document.write( "X=230.77 ml. of 80% mixture is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ",80*230.77+.15(600-230.77)=.4*600<BR>\n" );
document.write( "184.62+.15(369.23)=240<BR>\n" );
document.write( "184.62+55.38=240<BR>\n" );
document.write( "240=240 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );