document.write( "Question 339279: what quantity of x of 65% acid solution must be mixed with a 20% solution to produce 300ml of 45% \n" ); document.write( "

Algebra.Com's Answer #243617 by Fombitz(32388) $\"\"$ $\"About$

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Let x be the amount of 65% solution.
\n" ); document.write( "Let y be the amount of 20% solution.
\n" ); document.write( "1. $\"x%2By=300\"$
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\n" ); document.write( " $\"65x%2B20y=45%28300%29\"$
\n" ); document.write( " $\"65x%2B20y=13500\"$
\n" ); document.write( "2. $\"13x%2B4y=2700\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"y=300-x\"$
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( " $\"13x%2B4%28300-x%29=2700\"$
\n" ); document.write( " $\"13x%2B1200-4x=2700\"$
\n" ); document.write( " $\"9x=1500\"$
\n" ); document.write( " $\"highlight%28x=500%2F3%29\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"y=900%2F3-500%2F3\"$
\n" ); document.write( " $\"highlight%28y=400%2F3%29\"$
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