document.write( "Question 38898: The product of two consecutive odd intergers is 1 less than 4 times the sum. find the two intergers. \n" ); document.write( "
Algebra.Com's Answer #24360 by Paul(988)\"\" \"About 
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Let the two odd integers be.
\n" ); document.write( "x, and x+2
\n" ); document.write( "Equation:\r
\n" ); document.write( "\n" ); document.write( "(x)(x+2)=4(x+x+2)-1
\n" ); document.write( "\"x%5E2%2B2x=8x%2B8-1\"
\n" ); document.write( "\"x%5E2-6x-7=0\"
\n" ); document.write( "\"x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A1%2A-7+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "x=7
\n" ); document.write( "7+2=9
\n" ); document.write( "Hence, the two odd integers are 7 and 9.
\n" ); document.write( "Paul.
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