document.write( "Question 339915: Find tan -1 square root 3
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Algebra.Com's Answer #243577 by jim_thompson5910(35256)\"\" \"About 
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Since \"tan%28pi%2F3%29=sqrt%283%29\", this means that the inverse tangent of \"sqrt%283%29\" is \"pi%2F3\". Now just add \"pi\" to the answer to get \"pi%2F3%2Bpi=pi%2F3%2B3pi%2F3=4pi%2F3\" (this rotates the angle 180 degrees)\r
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\n" ); document.write( "\n" ); document.write( "So or where the angle is in the range from 0 to \"2pi\"
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