document.write( "Question 339836: Two cars are approaching an intersection. One is 3 miles South of the intersection and is moving at a constant speed of 40 mph. At the same time, the other car is 4 miles East of the intersection and is moving at a constant speed of 50 mph. Express the distance d between the cars as a function of time t. \n" ); document.write( "
Algebra.Com's Answer #243522 by jrfrunner(365)![]() ![]() You can put this solution on YOUR website! you basically have a right triangle formed by the movement of the cars, one from coming from the east and one coming from the south \n" ); document.write( "-- \n" ); document.write( "let d=ditance between the cars. \n" ); document.write( "let x=distance from car from the east to the meeting point \n" ); document.write( "let y=distance from car from the south to the meeting point \n" ); document.write( "distance=speed*time; d=s*t \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "-- \n" ); document.write( "at t=0, one car is 4 miles east and the other car is 3 miles south, so the distance between them, by the pythagorean theorem: \n" ); document.write( " \n" ); document.write( "-- \n" ); document.write( "as time goes forward, the distances from the east and the south shrink toward their meeting point. \n" ); document.write( "car from the east travels a distance: \n" ); document.write( "relative to the meeting point 4 miles away the distance shrinks \n" ); document.write( "as \n" ); document.write( "-- \n" ); document.write( "car from the south travels a distance: \n" ); document.write( "relative to the meeting point 3 miles away the distance shrinks \n" ); document.write( "as \n" ); document.write( "-- \n" ); document.write( " |