document.write( "Question 339836: Two cars are approaching an intersection. One is 3 miles South of the intersection and is moving at a constant speed of 40 mph. At the same time, the other car is 4 miles East of the intersection and is moving at a constant speed of 50 mph. Express the distance d between the cars as a function of time t. \n" ); document.write( "
Algebra.Com's Answer #243492 by mananth(16946)\"\" \"About 
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one car 3 miles 40 mph ----- t1 = 3/40 hours
\n" ); document.write( "second car 4 miles 50 mph----t2= 4/50 hours
\n" ); document.write( "...
\n" ); document.write( "they form a right angle with intersection.
\n" ); document.write( "the distance between the cars = hypotenuse.
\n" ); document.write( "..
\n" ); document.write( "\"d%5E2+=+%283%2F40%29%5E2+%2B+%284%2F50%29%5E2\"
\n" ); document.write( "Take square root of both sides
\n" ); document.write( "\"+d+=++sqrt%28%28t1%29%5E2%2B%28t2%29%5E2%29\"
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