document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339802>Question 339802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Half of Henry's age added to 1/3 of Daisy's age is 11 years.\r<BR>\n" );
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document.write( "Six years from now, the sum of their ages will be 40 years. How old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243454 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let h=henry's age and d=daisy's<BR>\n" );
document.write( "h/2 + d/3 = 11<BR>\n" );
document.write( "3h+2d=66 multiply each side by 6.<BR>\n" );
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document.write( "h+6+d+6=40<BR>\n" );
document.write( "h+d=28<BR>\n" );
document.write( "h=28-d<BR>\n" );
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document.write( "3(28-d)+2d=66<BR>\n" );
document.write( "84-3d+2d=66<BR>\n" );
document.write( "-d=-18<BR>\n" );
document.write( "d=18<BR>\n" );
document.write( "h=10 </SPAN>\n" );
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