document.write( "Question 339802: Half of Henry's age added to 1/3 of Daisy's age is 11 years.\r
\n" ); document.write( "\n" ); document.write( "Six years from now, the sum of their ages will be 40 years. How old is each? \n" ); document.write( "

Algebra.Com's Answer #243452 by mananth(16946) $\"\"$ $\"About$

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let henry's age = x
\n" ); document.write( "Daisy's age be y
\n" ); document.write( " $\"%28x%2F2%29+%2B%28y%2F3%29=+11%7D%7D%0D%0A%7B%7B%7B%283x%2B2y%29%2F6+=11\"$
\n" ); document.write( "3x+2y=6*11
\n" ); document.write( "3x+2y=66.....................1
\n" ); document.write( "...
\n" ); document.write( "6 years from now
\n" ); document.write( "x+6+y+6 = 40 years
\n" ); document.write( "x+y+12=40
\n" ); document.write( "x+y=40-12
\n" ); document.write( "x+y= 28 .......................2
\n" ); document.write( "multiply equation 2 by -2 and add the equations
\n" ); document.write( "-2x-2y=-56
\n" ); document.write( "3x+2y=66
\n" ); document.write( "x=10 Henry's age
\n" ); document.write( "plug value of x in eauation 2
\n" ); document.write( "x+y =28
\n" ); document.write( "10+y=28
\n" ); document.write( "y=28-10
\n" ); document.write( "y=18 Daisy's age \n" ); document.write( "

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