document.write( "Question 339803: 3 years ago, Rica was thrice as old as Dandy. 3 years hence, she will be twice as old. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #243440 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "3 years ago \n" ); document.write( "Let Dandy be x years \n" ); document.write( "Rica will be 3x \n" ); document.write( ".. \n" ); document.write( "3 years later\r \n" ); document.write( "\n" ); document.write( "Dandy will be x+6 \n" ); document.write( "Rica will be 3x+3 \n" ); document.write( ".. \n" ); document.write( "3x+6=2(x+6) \n" ); document.write( "3x+6 =2x+12 \n" ); document.write( "3x-2x=12-6 \n" ); document.write( "x=6 Dandy's age 3 years ago. so she will be 9 years now. \n" ); document.write( "Rica will be 3x+3 = 3*6+3= 21 years \n" ); document.write( " \n" ); document.write( " |