document.write( "Question 339803: 3 years ago, Rica was thrice as old as Dandy. 3 years hence, she will be twice as old. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #243440 by mananth(16946)\"\" \"About 
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\n" ); document.write( "3 years ago
\n" ); document.write( "Let Dandy be x years
\n" ); document.write( "Rica will be 3x
\n" ); document.write( "..
\n" ); document.write( "3 years later\r
\n" ); document.write( "\n" ); document.write( "Dandy will be x+6
\n" ); document.write( "Rica will be 3x+3
\n" ); document.write( "..
\n" ); document.write( "3x+6=2(x+6)
\n" ); document.write( "3x+6 =2x+12
\n" ); document.write( "3x-2x=12-6
\n" ); document.write( "x=6 Dandy's age 3 years ago. so she will be 9 years now.
\n" ); document.write( "Rica will be 3x+3 = 3*6+3= 21 years
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