document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339748>Question 339748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two integers whose product is 104 such that one of the integers is 3 less than twice the other integer. Thank you for showing me how to set this problem up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243400 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-3=2y<BR>\n" );
document.write( "x=2y+3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "xy=104<BR>\n" );
document.write( "y(2y+3)=104<BR>\n" );
document.write( "2y^2+3y-104=0<BR>\n" );
document.write( "2*-104=-208. The 2 factors of -208 whose sum is 3 are -13 and 16.<BR>\n" );
document.write( "2y^2+16y-13y-104=0<BR>\n" );
document.write( "2y(y+8)-13(y+8)=0 Factoring by grouping.<BR>\n" );
document.write( "(2y-13)(y+8)=0<BR>\n" );
document.write( ".<BR>\n" );
document.write( "y=-8<BR>\n" );
document.write( "2y=13, y=13/2 not an integer. Did the question ask for two numbers or integers?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );