document.write( "Question 339749: The area of a triangular sheet of paper is 28 square inches. One side of the triangle is 2 inches more than three times the length of the altitude to that side. Find the length of that side and the altitude to that side. Can you please set the solution in a step by step method. Thank you for your help. \n" ); document.write( "
Algebra.Com's Answer #243390 by mananth(16946)\"\" \"About 
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let altitude be x
\n" ); document.write( "base = 3x+2..
\n" ); document.write( "Area of triangle = \"%281%2F2%29+%2A+base%2Aaltitude\"
\n" ); document.write( "28 = \"%281%2F2%29%2Ax%2A%283x%2B2%29\"
\n" ); document.write( "multiply by 2
\n" ); document.write( "2*28= \"x%2A%283x%2B2%29\"
\n" ); document.write( "56=3x^2+2x
\n" ); document.write( "add -56 to both sides
\n" ); document.write( "56-56=3x^2+2x-56
\n" ); document.write( "3x^2+2x-56=0
\n" ); document.write( "solve using quadratic formula
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\"
\n" ); document.write( "a=3, b=2,c =-56
\n" ); document.write( "\"x1=%28-2%2Bsqrt%282%5E2-4%2A3%2A%28-56%29%29%29%2F%286%29\"
\n" ); document.write( "x1=4 inches
\n" ); document.write( "\"x1=%28-2-sqrt%282%5E2-4%2A3%2A%28-56%29%29%29%2F%286%29\"\r
\n" ); document.write( "\n" ); document.write( "x2=-4.66
\n" ); document.write( "ignore negative value.
\n" ); document.write( "Altitude = 5
\n" ); document.write( "base = 3x+2 = 15+2 =17 inches
\n" ); document.write( "
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