document.write( "Question 10695: FIND THE DIMENSIONS OF A RECTANGLE WHOSE PERIMETER IS 56 INCHES IF THE LENGTH IS THREE TIMES THE WIDTH. \n" ); document.write( "
Algebra.Com's Answer #24338 by tran3209(100)\"\" \"About 
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Let X be the width of the rectangle in inches: W = X.
\n" ); document.write( "The length of the rectangle is 3 times the width : L = 3X.
\n" ); document.write( "The perimeter of the rectangle : P = 2 W + 2 L
\n" ); document.write( " P = 2 ( W + L )
\n" ); document.write( "Replace W and L by X : P = 2 ( X + 3X )
\n" ); document.write( "Replace P by 56 \" : 56 = 2(4X)
\n" ); document.write( " 56 = 8 X
\n" ); document.write( " X = 56/8
\n" ); document.write( " X = 7\r
\n" ); document.write( "\n" ); document.write( "The Dimention of the rectangle Width 7\", Length 21\"
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