document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339646>Question 339646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of an alloy that is 70% silver should be melted with 60 grams of an alloy that is 20% silver to produce an alloy that is 30% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243360 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .70X+.20*60=.30(60+X)<BR>\n" );
document.write( ".70X+12=18-.30X<BR>\n" );
document.write( ".70X-.30X=18-12<BR>\n" );
document.write( ".40X=6<BR>\n" );
document.write( "X=6/.4<BR>\n" );
document.write( "X=15 OZ. OF 70% SILVER IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".70*15+.20*60=.30(60+15)<BR>\n" );
document.write( "10.5+12=.30*75<BR>\n" );
document.write( "22.5=22.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );