document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339696>Question 339696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangle is 360 square units. if one unit is added to both the length and the with of the rectangle the new area is 400 squre units. what are the dimensionsof the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243344 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x<BR>\n" );
document.write( "length be 360/x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "1 is added <BR>\n" );
document.write( "x+1<BR>\n" );
document.write( "360/x  + 1<BR>\n" );
document.write( "(x+1)(360/x +1)=400<BR>\n" );
document.write( "(x+1)(360+x)/x=400<BR>\n" );
document.write( "(x+1)(360+x)=400x<BR>\n" );
document.write( "360x+x^2+360+x=400x<BR>\n" );
document.write( "x^2-39x+360=0<BR>\n" );
document.write( "x^2-24x-15x+360=0<BR>\n" );
document.write( "x(x-24)-15(x-24)=0<BR>\n" );
document.write( "(x-24)(x-15)=0<BR>\n" );
document.write( "x=15 OR 24 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );