document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38741>Question 38741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 2y = 16<BR>\n" );
document.write( "2x + y = 9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24334 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "3x + 2y = 16<BR>\n" );
document.write( "2x + y = 9<BR>\n" );
document.write( "solve the second equation for y and substitute it into the first equation...<BR>\n" );
document.write( "y = -2x + 9<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x + 2(-2x + 9) = 16<BR>\n" );
document.write( "3x - 4x + 18 = 16<BR>\n" );
document.write( "-x = -2<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "then<BR>\n" );
document.write( "y = -2(2) + 9<BR>\n" );
document.write( "y = 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );