document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339615>Question 339615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
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document.write( "Could you please help me with my problem. <BR>\n" );
document.write( "It asks, Use the figure at the right to answer this question. \r<BR>\n" );
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document.write( "&#9787;&#9644;&#9644;&#9644;&#9644;|&#9644;&#9644;&#9644;&#9644;&#9787;&#9644;&#9644;&#9644;&#9644;|&#9644;&#9644;&#9644;&#9644;&#9787;<BR>\n" );
document.write( "S         T         U\r<BR>\n" );
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document.write( "Given: ST = 3x + 3 and TU = 2x + 9.<BR>\n" );
document.write( "a. What is the value of ST?<BR>\n" );
document.write( "b. What is the value of TU?\r<BR>\n" );
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document.write( "What I know is that ST = TU. But then I'm comepletely stuck on evrything else. I'm comepletely ignorant of how to do these problems. I'm asking for complete details on how to do these. Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243317 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ST = TU ___ so ___ 3x + 3 = 2x + 9 ___ so ___ x = 6\r<BR>\n" );
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document.write( "substituting ___ ST and TU equal 21 </SPAN>\n" );
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