document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339644>Question 339644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THis is simple and I can ge tthe answer but not the formula. Ed has $1.15. He has 43 more pennies than nickels. How many pennies and nickels does he have. THe answer is 12 nickels and 55 pennies but i just randomly guessed. It has to be easier than that </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243310 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"He has 43 more pennies than nickels\" ___ p = n + 43\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "\"Ed has $1.15\" ___ 5n + p = 115 ___ nickels worth 5 , pennies worth 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting for p ___ 5n + (n + 43) = 115 ___ 6n + 43 = 115 ___ 6n = 72 ___ n = 12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substituting ___ p = (12) + 43 = 55 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );