document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339622>Question 339622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find a number such that 24 more than half the number is twice the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243301 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the number we are looking for\r<BR>\n" );
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document.write( "24 + (1/2)(n) = 2n\r<BR>\n" );
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document.write( "24 + (n/2) = 2n\r<BR>\n" );
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document.write( "We now multiply every term by 2 to remove the fraction.\r<BR>\n" );
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document.write( "48 + n = 4n\r<BR>\n" );
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document.write( "48 = 4n - n\r<BR>\n" );
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document.write( "48 = 3n\r<BR>\n" );
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document.write( "48/3 = n\r<BR>\n" );
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document.write( "16 = n\r<BR>\n" );
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document.write( "The number we are looking for is 16.\r<BR>\n" );
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document.write( "Understand?\r<BR>\n" );
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